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3x^2-10=-17x
We move all terms to the left:
3x^2-10-(-17x)=0
We get rid of parentheses
3x^2+17x-10=0
a = 3; b = 17; c = -10;
Δ = b2-4ac
Δ = 172-4·3·(-10)
Δ = 409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{409}}{2*3}=\frac{-17-\sqrt{409}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{409}}{2*3}=\frac{-17+\sqrt{409}}{6} $
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